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0=x^2-11x+x^2
We move all terms to the left:
0-(x^2-11x+x^2)=0
We add all the numbers together, and all the variables
-(x^2-11x+x^2)=0
We get rid of parentheses
-x^2-x^2+11x=0
We add all the numbers together, and all the variables
-2x^2+11x=0
a = -2; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-2)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-2}=\frac{-22}{-4} =5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-2}=\frac{0}{-4} =0 $
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